Empirical Project 8 Working in R
Download the code
To download the code chunks used in this project, rightclick on the download link and select ‘Save Link As…’. You’ll need to save the code download to your working directory, and open it in RStudio.
Don’t forget to also download the data into your working directory by following the steps in this project.
Getting started in R
For this project you will need the following packages:
tidyverse
, to help with data manipulationreadxl
, to import an Excel spreadsheetknitr
, to format tables.
If you need to install any of these packages, run the following code:
install.packages(c("tidyverse", "readxl", "knitr"))
You can import the libraries now, or when they are used in the R walkthroughs below.
library(tidyverse)
library(readxl)
library(knitr)
Part 8.1 Cleaning and summarizing the data
Learning objectives for this part
 detect and correct entries in a dataset
 recode variables to make them easier to analyse
 calculate percentiles for subsets of the data.
So far we have been working with data that was formatted correctly. However, sometimes the datasets will be messier and we will need to clean the data before starting any analysis. Data cleaning involves checking that all variables are formatted correctly, all observations are entered correctly (e.g. no typos), and missing values are coded in a way that the software you are using can understand. Otherwise, the software will either not be able to analyse your data, or only analyse the observations it recognizes, which could lead to incorrect results and conclusions.
In the data we will use, the European Values Study (EVS) data has been converted to an Excel spreadsheet from another program, so there are some entries that were not converted correctly and some variables that need to be recoded (for example, replacing words with numbers, or replacing one number with another).
Download the EVS data and documentation:
 Download the EVS data.
 For the documentation, go to the data download site.
 Click on the ‘Data and Documents’ button in the middle of the page, then click the ‘Other Documents’ button and download the PDF file called ‘ZA4804_EVS_VariableCorrespondence.pdf’. This file contains information about each variable in the dataset (e.g. variable name and what it measures).
Although we will be performing our analysis in R, the data has been provided as an Excel spreadsheet, so look at the spreadsheet in Excel first to understand its structure.
 The Excel spreadsheet contains multiple worksheets, one for each wave, that need to be joined together to create a single ‘tibble’ (like a spreadsheet for R). The variable names currently do not tell us what the variable is, so we need to provide labels and short descriptions to avoid confusion.
 Using the
rbind
function, load each worksheet containing data (‘Wave 1’ through to ‘Wave 4’) and combine the worksheets into a single dataset.
 Use the PDF you have downloaded to create a label and a short description (attribute) for each variable using the
attr
function. (See R walkthrough 8.1 for details.) The second column of the PDF lists all variables in the dataset (alphabetically) and tells you what it measures.
R walkthrough 8.1 Importing the data into R
As we are importing an Excel file, we use the
read_excel
function from thereadxl
package. The file is calledProject8datafile.xlsx
and contains four worksheets that contain the data, named ‘Wave 1’ through to ‘Wave 4’. We will load the worksheets one by one and add them to the previous worksheets using therbind
function, which attaches objects with the same number of rows to each other. The final output is calledlifesat_data
.library(tidyverse) library(readxl) library(knitr) # Set your working directory to the correct folder. # Insert your file path for 'YOURFILEPATH'. setwd("YOURFILEPATH") lifesat_data < read_excel("Project8datafile.xlsx", sheet = "Wave 1") lifesat_data < rbind(lifesat_data, read_excel("Project8datafile.xlsx", sheet = "Wave 2")) lifesat_data < rbind(lifesat_data, read_excel("Project8datafile.xlsx", sheet = "Wave 3")) lifesat_data < rbind(lifesat_data, read_excel("Project8datafile.xlsx", sheet = "Wave 4"))
The variable names provided in the spreadsheet are not very specific (a combination of letters and numbers that don’t tell us what the variable measures), we can assign a label (
”labels”
) and a short description (shortDescription
, taken from the Variable Correspondence file) to each variable for reference later. Theattr
function does this for us (note that the order in each list should be the same as the order of the variable names).attr(lifesat_data, "labels") < c("EVSwave", "Country/region", "Respondent number", "Health", "Life satisfaction", "Work Q1", "Work Q2", "Work Q3", "Work Q4", "Work Q5", "Sex", "Age", "Marital status", "Number of children", "Education", "Employment", "Monthly household income") attr(lifesat_data, "shortDescription") < c("EVSwave", "Country/region", "Original respondent number", "State of health (subjective)", "Satisfaction with your life", "To develop talents you need to have a job", "Humiliating to receive money w/o working for it", "People who don't work become lazy", "Work is a duty towards society", "Work comes first even if it means less spare time", "Sex", "Age", "Marital status", "How many living children do you have", "Educational level (ISCEDcode one digit)", "Employment status", "Monthly household income (× 1,000s PPP euros)")
Throughout this project we will refer to the variables using their original names, but you can use the
attr
function again to look up the attributes of each variable (the following code uses the variableX028
to show how you can do this):attr(lifesat_data, "labels")[ attr(lifesat_data, "names") == "X028"]
## [1] "Employment"
attr(lifesat_data, "shortDescription")[ attr(lifesat_data, "names") == "X028"]
## [1] "Employment status"
In general, data dictionaries and variable correspondences are useful because they contain important information about what each variable represents and how it is measured, which usually cannot be summarized in a short variable name.
 Now we will take a closer look at how some of the variables were measured.
 Variable
A170
is reported life satisfaction on a scale of 1 (dissatisfied) to 10 (satisfied). Respondents answered the question ‘All things considered, how satisfied are you with your life as a whole these days?’ Discuss the assumptions needed to use this measure in interpersonal and crosscountry comparisons, and whether you think they are plausible. (You may find it helpful to refer to Box 2.1 of the OECD Guidelines on Measuring Subjective Wellbeing.)
 An individual’s employment status (variable X028) was selfreported. Explain whether misreporting of employment status is likely to be an issue, and give some factors that may affect the likelihood of misreporting in this context.
 Variables
C036
toC041
ask about an individual’s attitudes towards work. With selfreports, we may also be concerned that individuals are using a heuristic (rule of thumb) to answer the questions. Table 2.1 of the OECD Guidelines on Measuring Subjective Wellbeing lists some response biases and heuristics that individuals could use. Pick three that you think particularly apply to questions about life satisfaction or work ethic and describe how we might check whether this issue may be present in our data.
Before doing any data analysis, it is important to check that all variables are coded in a way that the software can recognize. This process involves checking how missing values are coded (usually these need to be coded in a particular way for each software), and that numerical variables (numbers) only contain numbers and not text (in order to calculate summary statistics).
 We will now check and clean the dataset so it is ready to use.
 Inspect the data and understand what type of data each variable is stored as. Currently, missing values are recorded as ‘.a’, but we would like them to be recorded as ‘NA’ (not available).
 Variable
A170
(life satisfaction) is currently a mixture of numbers (2 to 9) and words (‘Satisfied’ and ‘Dissatisfied’), but we would like it to be all numbers. Replace the word ‘Dissatisfied’ with the number 1, and the word ‘Satisfied’ with the number 10.
 Similarly, variable
X011_01
(number of children) has recorded no children as a word rather than a number. Replace ‘No children’ with the number 0.
 The variables
C036
toC041
should be replaced with numbers ranging from 1 (‘Strongly disagree’) to 5 (‘Strongly agree’) so we can take averages of them later. Similarly, variableA009
should be recoded as 1 = ‘Very Poor’, 2 = ‘Poor’, 3 = ‘Fair’, 4 = ‘Good’, 5 = ‘Very Good’.
 Split
X025A
into two variables, one for the number before the colon, and the other containing the words after the colon.
R walkthrough 8.2 Cleaning data and splitting variables
Inspect the data and recode missing values
R stores variables as different
types
depending on the kind of information the variable represents. For categorical data, where, as the name suggests, data is divided into a number of groups, such as country or occupation, the variables can be stored as text (chr
). Numerical data (numbers that do not represent categories) should be stored as numbers (num
), but sometimes R imports numerical values as text, which can cause problems later when we use these variables in calculations. Thestr
function shows what type each variable is being stored as.str(lifesat_data)
## Classes 'tbl_df', 'tbl' and 'data.frame': 164997 obs. of 17 variables: ## $ S002EVS: chr "19811984" "19811984" "19811984" "19811984" ... ## $ S003 : chr "Belgium" "Belgium" "Belgium" "Belgium" ... ## $ S006 : num 1001 1002 1003 1004 1005 ... ## $ A009 : chr "Fair" "Very good" "Poor" "Very good" ... ## $ A170 : chr "9" "9" "3" "9" ... ## $ C036 : chr ".a" ".a" ".a" ".a" ... ## $ C037 : chr ".a" ".a" ".a" ".a" ... ## $ C038 : chr ".a" ".a" ".a" ".a" ... ## $ C039 : chr ".a" ".a" ".a" ".a" ... ## $ C041 : chr ".a" ".a" ".a" ".a" ... ## $ X001 : chr "Male" "Male" "Male" "Female" ... ## $ X003 : num 53 30 61 60 60 19 38 39 44 76 ... ## $ X007 : chr "Single/Never married" "Married" "Separated" "Married" ... ## $ X011_01: chr ".a" ".a" ".a" ".a" ... ## $ X025A : chr ".a" ".a" ".a" ".a" ... ## $ X028 : chr "Full time" "Full time" "Unemployed" "Housewife" ... ## $ X047D : chr ".a" ".a" ".a" ".a" ... ##  attr(*, "labels")= chr "EVSwave" "Country/region" "Respondent number" "Health" ... ##  attr(*, "shortDescription")= chr "EVSwave" "Country/region" "Original respondent number" "State of health (subjective)" ...
You can see that some variables have the value
“.a”
, which is how missing values were coded in the original dataset. We start by recoding all missing values asNA
(which is how R recognizes and usually codes missing values).lifesat_data[lifesat_data == ".a"] < NA
Recode the life satisfaction variable
To recode the life satisfaction variable (
A170
), we can use logical indexing (asking R to check if a certain condition is satisfied or not) to select all observations where the variableA170
is equal to either ‘Dissatisfied’ or ‘Satisfied’ and assign the value 1 or 10 respectively. This variable was imported as achr
(text) instead ofnum
variable because some of the entries included text (the.a
for missing values). After changing the text into numerical values, we use theas.numeric
function to convert the variable into a numerical type.lifesat_data$A170[lifesat_data$A170 == "Dissatisfied"] < 1 lifesat_data$A170[lifesat_data$A170 == "Satisfied"] < 10 lifesat_data$A170 < as.numeric(lifesat_data$A170)
Recode the variable for number of children
We repeat this process (using logical indexing and then converting to numerical variable) for the variable indicating the number of children (
X011_01
).lifesat_data$X011_01[lifesat_data$X011_01 == "No children"] < 0 lifesat_data$X011_01 < as.numeric(lifesat_data$X011_01)
Replace text with numbers for multiple variables
When we have to recode multiple variables with the same mapping of text to numerical value (i.e. a word/phrase corresponds to the same number for all variables), we can use the
tidyverse
library and the piping (%>%
) operator to run the same sequence of steps in one go for all variables, instead of repeating the process used above for each variable. The punctuation%>%
links the commands together. (At this stage, don’t worry if you can’t understand exactly what this code does, as long as you can adapt it for similar situations. For a more detailed introduction to piping, see the University of Manchester’s Econometric Computing Learning Resource.)lifesat_data < lifesat_data %>% mutate_at(c("C036", "C037", "C038", "C039", "C041"), funs(recode(., "Strongly disagree" = "1", "Disagree" = "2", "Neither agree nor disagree" = "3", "Agree" = "4", "Strongly agree" = "5"))) %>% mutate_at(c("A009"), funs(recode(., "Very poor" = "1", "Poor" = "2", "Fair" = "3", "Good" = "4", "Very good" = "5"))) %>% mutate_at(c("A009", "C036", "C037", "C038", "C039", "C041", "X047D"), funs(as.numeric))
Split a variable containing numbers and text
To split the education variable (
X025A
) into two new columns, we use theseparate
function, which creates two new variables calledEducation_1
andEducation_2
containing the numeric value and the text description respectively. Then we use themutate_at
function to convertEducation_1
into a numeric variable.lifesat_data < lifesat_data %>% separate(X025A, c("Education_1", "Education_2"), " : ", remove = FALSE) %>% mutate_at("Education_1", funs(as.numeric))
Although the paper we are following only considered individuals aged 25–80 who were not students, we will retain the other observations in our analysis. However, we need to remove any observations that have missing values for A170
, X028
, or any of the other variables except X047D
. Removing missing data ensures that any summary statistics or analysis we do is done on the same set of data (without having to always account for the fact that some values are missing), and is fine as long as the data are missing at random (i.e. there is no particular reason why certain observations are missing and not others).

In your dataset, remove all rows in all waves that have missing data for A170. Do the same for:
 X003, X028, X007 and X001 in all waves
 A009 in Waves 1, 2, and 4 only
 C036, C037, C038, C039, C041 and X047D in Waves 3 and 4 only
 X011_01 and X025A, in Wave 4.
R walkthrough 8.3 gives guidance on how to do this.
R walkthrough 8.3 Dropping specific observations
As not all questions were asked in all waves, we have to be careful when dropping observations with missing values for certain questions, to avoid accidentally dropping an entire wave of data. For example, information on selfreported health (
A009
) was not recorded in Wave 3, and questions on work attitudes (C036
toC041
) and information on household income are only asked in Waves 3 and 4. Furthermore, information on the number of children (X011_01
) and education (X025A
) are only collected in the final wave.We will first use the
complete.cases
function to keep observations with complete information on variables present in all waves (X003
,A170
,X028
,X007
, andX001
—stored in the listinclude
). This function tells us which rows in the dataframe have complete information. When used in the codelifesat_data[complete.cases(lifesat_data[, include]), ]
, it tells R to only keep the rows that contain complete information of the variables in the listinclude
.include < names(lifesat_data) %in% c( "X003", "A170", "X028", "X007", "X001") lifesat_data < lifesat_data[ complete.cases(lifesat_data[, include]), ]
Next we will look at variables that were only present in some waves. For each variable/group of variables, we have to only look at the particular wave(s) in which the question was asked, then keep the observations with complete information on those variables. As before, we make lists of variables that only feature in Waves 1, 2, and 4 (
A009
—stored ininclude_wave_1_2_4
), Waves 3 and 4 (C036
toC041
,X047D
—stored ininclude_wave_3_4
), and Wave 4 only (X011_01
andX025A
—stored ininclude_wave_4
). Again we use thecomplete.cases
function, but combine it with the logical OR operator
to include all observations for waves that did not ask that question, along with the complete cases for that question in the other waves. For example, the first command keeps an observations if it is in Wave 1 (19811984) or Wave 2 (19901993), or is in Waves 3 or 4 with complete information.# A009 is not in Wave 3. include_wave_1_2_4 < names(lifesat_data) %in% c("A009") include_wave_3_4 < names(lifesat_data) %in% # Work attitudes and income are in Waves 3 and 4. c("C036", "C037", "C038", "C039", "C041", "X047D") # Number of children and education are in Wave 4. include_wave_4 < names(lifesat_data) %in% c("X011_01", "X025A") lifesat_data < lifesat_data %>% filter(S002EVS == "19811984"  S002EVS == "19901993"  complete.cases(lifesat_data[, include_wave_3_4])) lifesat_data < lifesat_data %>% filter(S002EVS != "20082010"  complete.cases(lifesat_data[, include_wave_4])) lifesat_data < lifesat_data %>% filter(S002EVS == "19992001"  complete.cases(lifesat_data[, include_wave_1_2_4]))
 We will now create two variables, work ethic and relative income, which we will use in our comparison of life satisfaction.
 Work ethic is measured as the average of
C036
toC041
. Create a new variable showing this work ethic measure.
 Since unemployed individuals and students may not have income, the study calculated relative income as the relative household income of that individual, measured as a deviation from the average income in that individual’s country. Explain the issues with using this method if the income distribution is skewed (for example, if it has a long right tail).
 Instead of using average income, we will define relative income as the percentile of that individual’s household in the income distribution. Create a new variable showing this information. (See R walkthrough 8.4 for one way to do this).
R walkthrough 8.4 Calculating averages and percentiles
Calculate average work ethic score
We use the
rowMeans
function to calculate the average work ethic score for each observation (workethic
) based on the five survey questions related to working attitudes (C036
toC041
).lifesat_data$work_ethic < rowMeans(lifesat_data[, c("C036", "C037", "C038", "C039", "C041")])
Calculate income percentiles for each individual
R provides a handy function (
ecdf
) to obtain an individual’s relative income as a percentile. As we want a separate income distribution for each wave, we use thegroup_by
function. Finally, we tidy up the results by converting each value into a percentage and rounding to a single decimal place.The
ecdf
function will not work if there is missing data. Since we don’t have income data for Waves 1 and 2, we will have to split the data when working out the percentiles. First we store all observations from Waves 3 and 4 separately in a temporary dataset (df.new
), only keep observations that have income values (!is.na(X047D)
), calculate the percentile values with theecdf
function, and save the values in a variable calledpercentile
(which will be ‘NA’ for Waves 1 and 2). Then we recombine this data with the original observations from Waves 1 and 2.# Create the percentile variable for Waves 3 and 4 df.new < lifesat_data %>% # Select Waves 3 and 4 subset(S002EVS %in% c("19992001", "20082010")) %>% # Drop observations with missing income data filter(!is.na(X047D)) %>% # Calculate the percentiles per wave group_by(S002EVS) %>% # Calculate relative income as a percentile mutate(., percentile = ecdf(X047D)(X047D)) %>% # Express the variable as a percentage mutate(., percentile = round(percentile * 100, 1)) # Recombine Waves 3 and 4 with the Waves 1 and 2 lifesat_data < lifesat_data %>% # Select Waves 1 and 2 subset(S002EVS %in% c("19811984", "19901993")) %>% # Create an empty variable so old and new dataframes are # same size mutate(., percentile = NA) %>% # Recombine the data bind_rows(., df.new)
 Now we have all the variables we need in the format we need. We will make some tables to summarize the data. Using the data for Wave 4:
 Create a table showing the breakdown of each country’s population according to employment status, with country (
S003
) as the row variable, and employment status (X028
) as the column variable. Express the values as percentages of the row total rather than as frequencies. Discuss any differences or similarities between countries that you find interesting.
 Create a new table as shown in Figure 8.1 (similar to Table 1 in the study ‘Employment status and subjective wellbeing’) and fill in the missing values. Life satisfaction is measured by
A170
. Summary tables such as these give a useful overview of what each variable looks like.
Male  Female  

Mean  Standard deviation  Mean  Standard deviation  
Life satisfaction  
Selfreported health  
Work ethic  
Age  
Education  
Number of children 
R walkthrough 8.5 Calculating summary statistics
Create a table showing employment status, by country
One of the most useful R functions to obtain summary information is
summarize
, which produces many different summary statistics for a set of data. First we select the data for Wave 4 and group it by country (S003
) and employment type (X028
). Then we use thesummarize
function to obtain the number of observations for each combination of country and employment type. With the data effectively grouped by country only (a single observation contains the number of observations for each level (category) ofX028
), we can use thesum
function to obtain a total count (number of observations) per country and calculate relative frequencies (saved asfreq
).lifesat_data %>% # Select Wave 4 only subset(S002EVS == "20082010") %>% # Group by country and employment group_by(S003, X028) %>% # Count the number of observations by group summarize(n = n()) %>% # Calculate the relative frequency (percentages) mutate(freq = round(n / sum(n), 4) * 100) %>% # Drop the count variable select(n) %>% # Reshape the data into a neat table spread(X028, freq) %>% kable(., format = "markdown")
S003  Full time Housewife Other Part time Retired Self employed Students Unemployed ::::::::: Albania  29.42 7.42 1.50 5.50 9.08 22.08 7.33 17.67 Armenia  23.86 20.92 1.14 8.09 18.38 5.96 6.70 14.95 Austria  39.80 7.24 1.89 9.95 25.49 5.02 8.39 2.22 Belarus  57.88 2.43 1.21 6.95 18.59 3.40 6.87 2.67 Belgium  42.89 5.96 3.72 8.94 23.01 3.57 5.21 6.70 Bosnia Herzegovina  34.06 9.33 0.82 2.90 14.67 3.08 8.15 26.99 Bulgaria  46.32 2.62 0.76 2.79 31.28 5.58 2.37 8.28 Croatia  41.58 3.37 0.93 2.78 26.01 2.86 8.75 13.72 Cyprus  46.32 13.68 1.29 2.84 24.39 6.58 1.68 3.23 Czech Republic  46.56 3.06 4.66 1.68 31.27 3.82 5.43 3.52 Denmark  55.89 0.28 1.32 6.69 24.32 5.94 4.15 1.41 Estonia  50.35 4.08 2.20 5.11 28.52 3.61 3.38 2.75 Finland  52.34 1.38 3.94 5.11 22.77 6.17 3.72 4.57 France  46.83 5.59 1.94 6.04 28.78 2.76 3.13 4.92 Georgia  19.46 11.60 0.81 6.57 19.38 7.06 2.60 32.52 Germany  38.44 4.58 3.03 8.44 28.64 2.97 2.67 11.23 Great Britain  33.50 7.32 4.01 11.23 28.99 5.72 1.40 7.82 Greece  28.49 17.42 0.40 2.97 26.73 13.72 6.18 4.09 Hungary  46.39 1.20 7.21 2.00 24.04 3.53 6.57 9.05 Iceland  54.50 2.25 6.01 9.91 7.06 11.41 4.95 3.90 Ireland  41.87 19.84 1.59 9.72 13.89 4.96 1.59 6.55 Italy  32.88 8.33 0.46 9.13 23.06 13.70 7.08 5.37 Kosovo  19.57 11.65 0.52 5.23 5.83 9.41 18.00 29.80 Latvia  52.05 6.18 2.34 3.76 23.22 3.26 4.26 4.93 Lithuania  50.13 4.11 2.89 5.16 23.97 3.41 6.04 4.29 Luxembourg  51.33 9.36 1.12 7.38 15.36 3.00 9.87 2.58 Macedonia  35.74 4.34 1.24 1.71 16.74 3.72 8.53 27.98 Malta  33.84 32.33 0.68 3.84 23.42 2.33 0.55 3.01 Moldova  30.49 7.24 1.87 7.58 25.64 4.86 4.43 17.89 Montenegro  39.02 4.63 0.60 2.14 16.64 4.97 4.80 27.19 Netherlands  32.40 9.52 3.68 18.24 27.76 6.48 0.80 1.12 Northern Cyprus  31.19 19.55 2.23 5.20 8.91 8.91 13.61 10.40 Northern Ireland  30.10 10.36 4.53 8.74 29.45 3.56 1.29 11.97 Norway  53.23 2.22 6.55 9.48 12.60 8.17 7.06 0.71 Poland  41.81 6.00 0.10 3.14 28.00 5.81 7.62 7.52 Portugal  46.20 5.24 1.57 3.27 33.51 1.70 1.05 7.46 Romania  41.07 10.54 1.95 3.22 33.95 3.02 3.61 2.63 Russian Federation  54.36 5.81 2.72 5.08 23.77 1.27 2.72 4.26 Serbia  34.21 5.02 1.07 2.38 25.16 6.91 4.11 21.13 Slovakia  40.98 1.73 4.89 2.21 39.73 3.55 1.25 5.66 Slovenia  47.44 2.50 2.75 1.25 31.59 4.37 6.99 3.12 Spain  41.52 16.30 0.11 4.63 19.93 6.28 3.19 8.04 Sweden  54.82 0.38 6.60 7.36 15.36 7.23 4.06 4.19 Switzerland  48.50 6.42 3.21 14.03 21.31 2.89 1.39 2.25 Turkey  16.42 42.39 0.60 2.14 10.00 7.66 5.92 14.88 Ukraine  40.92 6.79 1.02 4.84 32.09 4.41 3.23 6.71
Calculate summary statistics by gender
We can also obtain summary statistics on a number of variables at the same time using the
summarize_at
function. To obtain the mean value for each of the required variables, grouped by the gender variable (X001
), we can use the piping operator again:# Obtain mean value lifesat_data %>% # We only require Wave 4. subset(S002EVS == "20082010") %>% # Group by gender group_by(X001) %>% summarize_at(c("A009", "A170", "work_ethic", "X003", "Education_1", "X011_01"), mean)
## # A tibble: 2 x 7 ## X001 A009 A170 work_ethic X003 Education_1 X011_01 ## <chr> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> ## 1 Female 3.60 6.93 3.64 47.3 3.05 1.69 ## 2 Male 3.77 7.03 3.72 46.9 3.14 1.55
We can repeat the same steps to obtain the standard deviation, again grouped by gender.
# Obtain standard deviation lifesat_data %>% subset(S002EVS == "20082010") %>% group_by(X001) %>% summarize_at(c("A009", "A170", "work_ethic", "X003", "Education_1", "X011_01"), sd)
## # A tibble: 2 x 7 ## X001 A009 A170 work_ethic X003 Education_1 X011_01 ## <chr> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> ## 1 Female 0.969 2.32 0.765 17.5 1.40 1.39 ## 2 Male 0.929 2.28 0.757 17.4 1.31 1.43
We can combine these two operations into a single code block and ask
summarize_at
to perform multiple functions on multiple variables at the same time.# Obtain mean and standard deviations lifesat_data %>% subset(S002EVS == "20082010") %>% group_by(X001) %>% summarise_at(c("A009", "A170", "work_ethic", "X003", "Education_1", "X011_01"), funs(mean, sd))
## # A tibble: 2 x 13 ## X001 A009_mean A170_mean work_ethic_mean X003_mean Education_1_mean ## <chr> <dbl> <dbl> <dbl> <dbl> <dbl> ## 1 Female 3.60 6.93 3.64 47.3 3.05 ## 2 Male 3.77 7.03 3.72 46.9 3.14 ## # ... with 7 more variables: X011_01_mean <dbl>, A009_sd <dbl>, ## # A170_sd <dbl>, work_ethic_sd <dbl>, X003_sd <dbl>, ## # Education_1_sd <dbl>, X011_01_sd <dbl>
In this example, R automatically appends the function name (in this case,
_mean
or_sd
) to the end of the variables. If you need these variables in subsequent calculations, you need to reformat the data and variable names.
Part 8.2 Visualizing the data
Note
You will need to have done Questions 1–5 in Part 8.1 before doing this part.
Learning objectives for this part
 use column charts, line charts, and scatterplots to visualize data
 calculate and interpret correlation coefficients.
We will now create some summary charts of the selfreported measures (work ethic and life satisfaction), starting with column charts to show the distributions of values. Along with employment status, these are the main variables of interest, so it is important to look at them carefully before doing further data analysis.
The distribution of work ethic and life satisfaction may vary across countries but may also change over time within a country, especially since the surveys are conducted around once a decade. To compare distributions for a particular country over time, we have to use the same horizontal axis, so we will first need to make a separate frequency table for each distribution of interest (survey wave). Also, since the number of people surveyed in each wave may differ, we will use percentages instead of frequencies as the vertical axis variable.
 Use the data from Wave 3 and Wave 4 only, for three countries of your choice:
 For each of your chosen countries create a frequency table that contains the frequency of each unique value of the work ethic scores. Also include the percentage of individuals at each value, grouped by Wave 3 and Wave 4 separately.
 Plot a separate column chart for each country to show the distribution of work ethic scores in Wave 3, with the percentage of individuals on the vertical axis and the range of work ethic scores on the horizontal axis. On each chart, plot the distribution of scores in Wave 4 on top of the Wave 3 distribution.
 Based on your charts from 1(b), does it appear that the attitudes towards work in each country of your choice have changed over time? (Hint: For example, look at where the distribution is centred, the percentages of observations on the left tail or the right tail of the distribution, and how spread out the data is.)
R walkthrough 8.6 Calculating frequencies and percentages
First we need to create a frequency table of the
work_ethic
variable for each wave. This variable only takes values from 1.0 to 5.0 in increments of 0.2 (since it is an average of five whole numbers), so we can group by each value and count the number of observations in each group using thesummarize
function. Once we have counted the number of observations that have each value (separately for each wave), we compute the percentages by dividing these numbers by the total number of observations for that wave. For example, if there are 50 observations between 1 and 1.2, and 1,000 observations in that wave, the percentage would be 5%.waves < c("19992001", "20082010") df.new < lifesat_data %>% # Select Waves 3 and 4 subset(., S002EVS %in% waves) %>% # We use Germany in this example. subset(., S003 == "Germany") %>% # Group by each wave and the discrete values of # work_ethic group_by(S002EVS, work_ethic) %>% summarize (freq = n()) %>% mutate(percentage = (freq / sum(freq))*100)
The frequencies and percentages are saved in a new dataframe called
df.new
. If you want to look at it, typeview(df.new)
into the console window. Now that we have the percentages and frequency data, we useggplot
to plot a column chart. To overlay the column charts for both waves and make sure that the plot for each wave is visible, we use thealpha
option in thegeom_bar
function to set the transparency level (try changing the transparency to see how it affects your chart’s appearance).p < ggplot(df.new, aes(work_ethic, percentage, fill = S002EVS, color = S002EVS)) + # Set the colour and fill of each wave geom_bar(stat = "identity", position = "identity", alpha = 0.2) + theme_bw() + ggtitle(paste("Distribution of work ethic for Germany")) print(p)
 We will use line charts to make a similar comparison for life satisfaction (
A170
) over time. Using data for countries that are present in Waves 1 to 4:
 Create a table showing the average life satisfaction, by wave (column variable) and by country (row variable).
 Plot a line chart with wave number (1 to 4) on the horizontal axis and the average life satisfaction on the vertical axis.
 From your results in 2(a) and (b), how has the distribution of life satisfaction changed over time? What other information about the distribution of life satisfaction could we use to supplement these results?
 Choose one or two countries and research events that could explain the observed changes in average life satisfaction over time shown in 2(a) and (b).
R walkthrough 8.7 Plotting multiple lines on a chart
Calculate average life satisfaction, by wave and country
Before we can plot the line charts, we have to calculate the average life satisfaction for each country in each wave.
In R walkthrough 8.5 we produced summary tables, grouped by country and employment status. We will copy this process, but now we only require mean values. Countries that do not report the life satisfaction variable for all waves will have an average life satisfaction of ‘NA’. Since each country is represented by a row in the summary table, we use the
rowwise
andna.omit
functions to drop any countries that do not have a value for the average life satisfaction for all four waves.df.new < lifesat_data %>% group_by(S002EVS, S003) %>% # Calculate average life satisfaction per wave and country summarize(avg_lifesat = round(mean(A170), 2)) %>% # Reshape the data to one row per country spread(S002EVS, avg_lifesat) %>% # Set subsequent operations to be performed on each row rowwise() %>% # Drop any rows with missing observations na.omit() %>% print()
## # A tibble: 11 x 5 ## S003 `19811984` `19901993` `19992001` `20082010` ## <chr> <dbl> <dbl> <dbl> <dbl> ## 1 Belgium 7.37 7.6 7.42 7.63 ## 2 Denmark 8.21 8.17 8.31 8.41 ## 3 France 6.71 6.77 6.98 7.05 ## 4 Germany 7.22 7.03 7.43 6.77 ## 5 Iceland 8.05 8.01 8.08 8.07 ## 6 Ireland 7.82 7.88 8.21 7.82 ## 7 Italy 6.65 7.3 7.18 7.4 ## 8 Netherlands 7.75 7.77 7.83 7.99 ## 9 Northern Ireland 7.66 7.88 8.07 7.82 ## 10 Spain 6.6 7.15 6.97 7.29 ## 11 Sweden 8.03 7.99 7.62 7.68
Create a line chart for average life satisfaction
To draw the lines for all countries on a single plot, we need to use the
gather
function to transform the data into the correct format to use inggplot
.df.new %>% gather(Wave, mean, `19811984`:`20082010`) %>% # Group the data by country ggplot(., aes(x = Wave, y = mean, color = S003)) + geom_line(aes(group = S003, linetype = S003), size = 1) + theme_bw()
 correlation coefficient
 A numerical measure, ranging between 1 and −1, of how closely associated two variables are—whether they tend to rise and fall together, or move in opposite directions. A positive coefficient indicates that when one variable takes a high (low) value, the other tends to be high (low) too, and a negative coefficient indicates that when one variable is high the other is likely to be low. A value of 1 or −1 indicates that knowing the value of one of the variables would allow you to perfectly predict the value of the other. A value of 0 indicates that knowing one of the variables provides no information about the value of the other.
After describing patterns in our main variables over time, we will use correlation coefficients and scatter plots to look at the relationship between these variables and the other variables in our dataset.
 Using the Wave 4 data:
 Create a table as shown in Figure 8.4 and calculate the required correlation coefficients. For employment status and gender, you will need to create new variables: fulltime employment should be equal to 1 if fulltime employed and 0 if unemployed, and treated as missing data (left as a blank cell) otherwise. Gender should be 0 if male and 1 if female.
Variable  Life satisfaction  Work ethic 

Age  
Education  
Fulltime employment  
Gender  
Selfreported health  
Income  
Number of children  
Relative income  
Life satisfaction  1  
Work ethic  1 
 Interpret the coefficients, paying close attention to how the variables are coded. (For example, you could comment on the absolute magnitude and sign of the coefficients). Explain whether the relationships implied by the coefficients are what you expected (for example, would you expect life satisfaction to increase or decrease with health, income, etc.)
R walkthrough 8.8 Creating dummy variables and calculating correlation coefficients
To obtain the correlation coefficients between variables, we have to make sure that all variables are numeric. However, the data on sex and employment status are coded using text, so we need to create two new variables (
gender
andemployment
). (We choose to create a new variable rather than overwrite the original variable so that even if we make a mistake, the raw data is still preserved). We can use theifelse
function to make the value of the variable conditional on whether a logical statement (e.g.X001 == "Male"
) is satisfied or not. As shown below, we can nestifelse
statements to create more complex conditions, which is useful if the variable contains more than two values. We used twoifelse
statements for the unemployment variable (X028
) so that the new variable will be 1 for fulltime employed, 0 for unemployed, and NA if neither condition is satisfied.Although we had previously removed observations with missing values (‘NA’), we have reintroduced ‘NA’ values in the previous step when creating the
employment
variable. This would cause problems when obtaining the correlation coefficients using thecor
function, so we include the optionuse = "pairwise.complete.obs"
to exclude observations containing ‘NA’ from the calculations.lifesat_data %>% # We only require Wave 4. subset(S002EVS == "20082010") %>% # Create a gender variable mutate(gender = as.numeric( ifelse(X001 == "Male", 0, 1))) %>% # Provide nested condition for employment mutate(employment = as.numeric( ifelse(X028 == "Full time", 1, ifelse(X028 == "Unemployed", 0, NA)))) %>% select(X003, Education_1, employment, gender, A009, X047D, X011_01, percentile, A170, work_ethic) %>% # Store output in matrix cor(., use = "pairwise.complete.obs") > M # Only interested in two columns, so use matrix indexing M[, c("A170", "work_ethic")]
## A170 work_ethic ## X003 0.08220504 0.13333312 ## Education_1 0.09363900 0.14535643 ## employment 0.18387286 0.02710835 ## gender 0.02105535 0.04781557 ## A009 0.37560287 0.07320865 ## X047D 0.23542497 0.15226999 ## X011_01 0.01729372 0.08925452 ## percentile 0.29592968 0.18679869 ## A170 1.00000000 0.03352464 ## work_ethic 0.03352464 1.00000000
Next we will look at the relationship between employment status and life satisfaction, and investigate the paper’s hypothesis that this relationship varies with a country’s average work ethic.
 Using the data from Wave 4, carry out the following:
 Create a table showing the average life satisfaction according to employment status (showing the fulltime employed, retired, and unemployed categories only) with country (
S003
) as the row variable, and employment status (X028
) as the column variable. Comment on any differences in average life satisfaction between these three groups, and whether social norms is a plausible explanation for these differences.
 Use the table from Question 4(a) to calculate the difference in average life satisfaction (fulltime employed minus unemployed, and fulltime employed minus retired).
 Make a separate scatterplot for each of these differences in life satisfaction, with average work ethic on the horizontal axis and difference in life satisfaction on the vertical axis.
 For each difference (employed vs unemployed, employed vs retired), calculate and interpret the correlation coefficient between average work ethic and difference in life satisfaction.
R walkthrough 8.9 Calculating group means
Calculate average life satisfaction and differences in average life satisfaction
We can achieve the tasks in Question 4(a) and (b) in one go using an approach similar to that used in R walkthrough 8.5, although now we are interested in calculating the average life satisfaction by country and employment type. Once we have tabulated these means, we can compute the difference in the average values. We will create two new variables:
D1
for the difference between the average life satisfaction for fulltime employed and unemployed, andD2
for the difference in average life satisfaction for fulltime employed and retired individuals.# Set the employment types that we want to report employment_list = c("Full time", "Retired", "Unemployed") df.employment < lifesat_data %>% # Select Wave 4 subset(S002EVS == "20082010") %>% # Select only observations with these employment types subset(X028 %in% employment_list) %>% # Group by country and then employment type group_by(S003, X028) %>% # Calculate the mean by country/employment type group summarize(mean = mean(A170)) %>% # Reshape to one row per country spread(X028, mean) %>% # Create the difference in means mutate(D1 = `Full time`  Unemployed, D2 = `Full time`  Retired) kable(df.employment, format = "markdown")
S003  Full time Retired Unemployed D1 D2 :::::: Albania  6.634561 5.807339 6.066038 0.5685232 0.8272215 Armenia  6.037671 4.853333 5.459016 0.5786548 1.1843379 Austria  7.435950 7.741936 6.074074 1.3618763 0.3059851 Belarus  6.099162 5.617391 5.606061 0.4931014 0.4817707 Belgium  7.717014 7.834951 6.366667 1.3503472 0.1179376 Bosnia Herzegovina  7.332447 7.006173 6.771812 0.5606347 0.3262740 Bulgaria  6.177007 4.972973 4.693878 1.4831297 1.2040343 Croatia  7.305668 6.478964 7.165644 0.1400238 0.8267036 Cyprus  7.384401 7.031746 6.560000 0.8244011 0.3526551 Czech Republic  7.302135 6.885086 6.065217 1.2369173 0.4170491 Denmark  8.541315 8.205426 7.200000 1.3413153 0.3358890 Estonia  6.925117 6.253444 4.971429 1.9536884 0.6716735 Finland  7.817073 8.018692 5.767442 2.0496313 0.2016184 France  7.200637 6.974093 6.242424 0.9582127 0.2265437 Georgia  6.116667 4.690377 5.421446 0.6952203 1.4262901 Germany  7.258114 6.848548 4.608466 2.6496488 0.4095667 Great Britain  7.532934 7.930796 6.025641 1.5072931 0.3978617 Greece  7.152113 6.621622 5.980392 1.1717205 0.5304911 Hungary  6.645941 5.890000 4.858407 1.7875342 0.7559413 Iceland  8.203857 8.446808 7.230769 0.9730875 0.2429518 Ireland  7.895735 7.828571 7.181818 0.7139164 0.0671632 Italy  7.427083 7.440594 6.595745 0.8313387 0.0135107 Kosovo  6.297710 6.038462 6.784461 0.4867512 0.2592484 Latvia  6.516854 5.928058 5.305085 1.2117692 0.5887964 Lithuania  6.586387 5.631387 4.530612 2.0557752 0.9550006 Luxembourg  7.866221 8.240224 5.500000 2.3662207 0.3740027 Macedonia  7.193059 6.671296 6.609418 0.5836403 0.5217623 Malta  7.700405 7.760234 5.954546 1.7458594 0.0598291 Moldova  7.117318 5.976744 6.071429 1.0458899 1.1405742 Montenegro  7.632967 7.216495 7.473186 0.1597809 0.4164722 Netherlands  8.037037 7.945245 7.000000 1.0370370 0.0917921 Northern Cyprus  6.738095 6.444444 5.642857 1.0952381 0.2936508 Northern Ireland  7.677419 7.769231 7.540540 0.1368788 0.0918114 Norway  8.193182 8.264000 8.000000 0.1931818 0.0708182 Poland  7.464692 6.574830 7.063291 0.4014013 0.8898626 Portugal  6.838527 5.878906 5.438597 1.3999304 0.9596207 Romania  7.135392 6.574713 7.407407 0.2720155 0.5606793 Russian Federation  6.861436 5.702290 6.404255 0.4571804 1.1591456 Serbia  7.170673 6.673203 6.731517 0.4391556 0.4974705 Slovakia  7.468384 6.710145 6.118644 1.3497400 0.7582391 Slovenia  7.834211 7.130435 6.760000 1.0742105 0.7037757 Spain  7.336870 7.209945 7.191781 0.1450892 0.1269253 Sweden  7.877315 8.173554 6.515151 1.3621633 0.2962389 Switzerland  8.037528 8.115578 5.761905 2.2756228 0.0780503 Turkey  6.500000 6.606965 5.762542 0.7374582 0.1069652 Ukraine  6.344398 5.444444 4.949367 1.3950313 0.8999539
Make a scatterplot, sorted according to work ethic
In order to plot the differences ordered by the average work ethic, we first need to get all data from Wave 4 (using
subset
), summarize thework_ethic
variable by country (group_by
thensummarize
), and store the results in a temporary dataframe (df.work.ethic
).df.work_ethic < lifesat_data %>% subset(S002EVS == "20082010") %>% select(S003, work_ethic) %>% group_by(S003) %>% summarize(mean_work = mean(work_ethic))
We can now combine the average
work_ethic
data with the table containing the difference in means (usinginner_join
to match the data correctly by country) and make a scatterplot usingggplot
. This process can be repeated for the difference in means between fulltime employed and retired individuals by changingy = D1
toy = D2
in theggplot
function.df.employment %>% # Combine with the average work ethic data inner_join(., df.work_ethic, by = "S003") %>% ggplot(., aes(y = D1, x = mean_work)) + geom_point(stat = "identity") + xlab("Work ethic") + ylab("Difference") + ggtitle("Difference in wellbeing between the fulltime employed and the unemployed") + theme_bw() + # Rotate the country names theme(axis.text.x = element_text( angle = 90, hjust = 1), plot.title = element_text(hjust = 0.5))
To calculate correlation coefficients, use the
cor
function. You can see that the correlation between average work ethic and difference in life satisfaction is quite weak for employed vs unemployed, but moderate and positive for employed vs retired.# Fulltime vs unemployed cor(df.employment$D1, df.work_ethic$mean_work)
## [1] 0.1575654
# Fulltime vs retired cor(df.employment$D2, df.work_ethic$mean_work)
## [1] 0.4842609
So far we have described the data using tables and charts, but have not made any statements about whether what we observe is consistent with an assumption that work ethic has no bearing on differences in life satisfaction between different subgroups. In the next part, we will assess the relationship between employment status and life satisfaction and assess whether the observed data lead us to reject the above assumption.
Part 8.3 Confidence intervals for difference in the mean
Note
You will need to have done Questions 1–5 in Part 8.1 before doing this part. Part 8.2 is not necessary but is helpful to get an idea of what the data looks like.
Learning objectives for this part
 calculate and interpret confidence intervals for the difference in means between two groups.
The aim of this project was to look at the empirical relationship between employment and life satisfaction.
When we calculate differences between groups, we collect evidence which may or may not support a hypothesis that life satisfaction is identical between different subgroups. Economists often call this testing for statistical significance. In Part 6.2 of Empirical Project 6, we constructed 95% confidence intervals for means, and used a rule of thumb to assess our hypothesis that the two groups considered were identical (at the population level) in the variable of interest. Now we will learn how to construct confidence intervals for the difference in two means, which allows us to make such a judgment on the basis of a single confidence interval.
Remember that the width of a confidence interval depends on the standard deviation and number of observations. (Read Part 6.2 of Empirical Project 6 to understand why.) When making a confidence interval for a sample mean (such as the mean life satisfaction of the unemployed), we use the sample standard deviation and number of observations in that sample (unemployed people) to obtain the standard error of the sample mean.
When we look at the difference in means (such as life satisfaction of employed minus unemployed), we are using data from two groups (the unemployed and the employed) to make one confidence interval. To calculate the standard error for the difference in means, we use the standard errors (SE) of each group:
This formula requires the two groups of data to be independent, meaning that the data from one group is not related, paired, or matched with data from the other group. This assumption is reasonable for the life satisfaction data we are using. However, if the two groups of data are not independent, for example if the same people generated both groups of data (as in the public goods experiments of Empirical Project 2), then we cannot use this formula.
Once we have the new standard error and number of observations, we can calculate the width of the confidence interval (distance from the mean to one end of the interval) as before. The width of the confidence interval tells us how precisely the difference in means was estimated, and this precision tells us how compatible the sample data is with the hypothesis that there is no difference between the population means. If the value 0 falls outside the 95% confidence interval, this implies that the data is unlikely to have been sampled from a population with equal population means. For example, if the estimated difference is positive, and the 95% confidence interval is not wide enough to include 0, we can be reasonably confident that the true difference is positive too. In other words, it tells us that the pvalue for the difference we have found is less than 0.05, so we would be very unlikely to find such a big difference if the population means were in fact identical.
In Figure 8.6, for Great Britain, we can be reasonably confident that the true difference in average life satisfaction between the fulltime employed and the unemployed is positive. However, for Spain, we do not have strong evidence of a real difference in mean life satisfaction.
 We will apply this method to make confidence intervals for differences in life satisfaction. Choose three countries: one with an average work ethic in the top third of scores, one in the middle third, and one in the lower third. (See R walkthrough 6.3 for help on calculating confidence intervals and adding them to a chart.)

In Question 4 of Part 8.2 you computed the average life satisfaction score by country and employment type (using Wave 4 data). Repeat this procedure to obtain the standard error for the means for each of your chosen countries.
Create a table for these countries, showing the average life satisfaction score, standard deviation of life satisfaction, and number of observations, with country (
S003
) as the row variable, and employment status (fulltime employed, retired, and unemployed only) as the column variable.
 Use your table from Question 1(a) to calculate the difference in means (fulltime employed minus unemployed, and fulltime employed minus retired), the standard deviation of these differences, the number of observations, and the confidence interval.
 Use R’s
t.test
function to determine the 95% confidence interval width of the difference in means and compare your results with Question 1(b).
 Plot a column chart for your chosen countries showing the difference in life satisfaction (employed vs unemployed and employed vs retired) on the vertical axis, and country on the horizontal axis (sorted according to low, medium, and high work ethic). Add the confidence intervals from Question 1(c) to your chart.
 Interpret your findings from Question 1(d), commenting on the size of the observed differences in means, and the precision of your estimates.
R walkthrough 8.10 Calculating confidence intervals and adding error bars
We will use Turkey, Spain, and Great Britain as example countries in the top, middle, and bottom third of work ethic scores respectively.
In the tasks in Questions 1(a) and (b) we will obtain the means, standard errors, and 95% confidence intervals stepbystep, then for Question 1(c) we show how to use a shortcut to obtain confidence intervals from a single function.
Calculate confidence intervals manually
We obtained the difference in means in R walkthrough 8.9 (
D1
andD2
), so now we can calculate the standard error of the means for each country of interest.# List chosen countries country_list < c("Turkey", "Spain", "Great Britain") df.employment.se < lifesat_data %>% # Select Wave 4 subset(S002EVS == "20082010") %>% # Select the employment types we are interested in subset(X028 %in% employment_list) %>% # Select countries subset(S003 %in% country_list) %>% # Group by country and employment type group_by(S003, X028) %>% # Calculate the standard error of each group mean summarize(se = sd(A170) / sqrt(n())) %>% spread(X028, se) %>% # Calculate the SE of difference mutate(D1_SE = sqrt(`Full time`^2 + Unemployed^2), D2_SE = sqrt(`Full time`^2 + Retired^2))
We can now combine the standard errors with the difference in means, and compute the 95% confidence interval width.
df.employment < df.employment %>% # Select chosen countries subset(S003 %in% country_list) %>% # We only need the differences. select(`Full time`, Retired, Unemployed) %>% # Join the means with the respective SEs inner_join(., df.employment.se, by = "S003") %>% select(`Full time`, Retired, Unemployed) %>% # Compute confidence interval width for both differences mutate(CI_1 = 1.96 * D1_SE, CI_2 = 1.96 * D2_SE) %>% print()
## # A tibble: 3 x 7 ## # Groups: S003 [3] ## S003 D1 D2 D1_SE D2_SE CI_1 CI_2 ## <chr> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> ## 1 Great Britain 1.51 0.398 0.267 0.154 0.524 0.302 ## 2 Spain 0.145 0.127 0.265 0.168 0.520 0.330 ## 3 Turkey 0.737 0.107 0.229 0.231 0.449 0.452
We now have a table containing the difference in means, the standard error of the difference in means, and the confidence intervals for each of the two differences. (Recall that
D1
is the difference between the average life satisfaction for fulltime employed and unemployed, andD2
is the difference in average life satisfaction for fulltime employed and retired individuals.)Calculate confidence intervals using the
t.test
functionWe could obtain the confidence intervals directly by using the
t.test
function. First we need to prepare the data in two groups. In the following example we go through the difference in average life satisfaction for fulltime employed and unemployed individuals in Turkey, but the process can be repeated for the difference between fulltime employed and retired individuals by changing the code appropriately (also for your other two chosen countries).We start by selecting the data for fulltime and unemployed people in Turkey, and storing it in two separate temporary matrices (arrays of rows and columns) called
turkey_full
andturkey_unemployed
respectively, which is the format needed for thet.test
function.turkey_full < lifesat_data %>% # Select Wave 4 only subset(S002EVS == "20082010") %>% # Select country subset(S003 == "Turkey") %>% # Select employment type subset(X028 == "Full time") %>% # We only need the life satisfaction data. select(A170) %>% # We have to set it as a matrix for t.test. as.matrix() # Repeat for second group turkey_unemployed < lifesat_data %>% subset(S002EVS == "20082010") %>% subset(S003 == "Turkey") %>% subset(X028 == "Unemployed") %>% select(A170) %>% as.matrix()
We can now use the
t.test
function on the two newly created matrices. We also set the confidence level to 95%. Thet.test
function produces quite a bit of output, but we are only interested in the confidence interval, which we can obtain by using$conf.int
.turkey_ci < t.test(turkey_full, turkey_unemployed, conf.level = 0.95)$conf.int turkey_ci
## [1] 0.2873459 1.1875704 ## attr(,"conf.level") ## [1] 0.95
We can then calculate the difference in means by finding the midpoint of the interval (
(turkey_ci[2] + turkey_ci[1])/2
is 0.7374582), which should be the same as the figures obtained in Question 1(b) (df.employment[3, 2]
is 0.7374582).Add error bars to the column charts
We can now use these confidence intervals (and widths) to add error bars to our column charts. To do so, we use the
geom_errorbar
option, and specify the lower and upper levels of the confidence interval for theymin
andymax
options respectively. In this case it is easier to use the results from Questions 1(a) and (b), as we already have the values for the difference in means and the CI width stored as variables.ggplot(df.employment, aes(x = S003, y = D1)) + geom_bar(stat = "identity") + geom_errorbar(aes(ymin = D1  CI_1, ymax = D1 + CI_1), width = .2) + ylab("Difference in means") + xlab("Country") + theme_bw() + ggtitle("Difference in wellbeing (fulltime and unemployed)")
Again, this can be repeated for the difference in life satisfaction between fulltime employed and retired. Remember to change
y = D1
toy = D2
, and change the upper and lower limits for the error bars.
 The method we used to compare life satisfaction relied on making comparisons between people with different employment statuses, but a person’s employment status is not entirely random. We cannot therefore make causal statements such as ‘being unemployed causes life satisfaction to decrease’. Describe how we could use the following methods to assess better the effect of being unemployed on life satisfaction, and make some statements about causality:
 a natural experiment
 panel data (data on the same individuals, taken at different points in time).